20x^2+2x=1/10

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Solution for 20x^2+2x=1/10 equation: 


x in (-oo:+oo)

20*x^2+2*x = 1/10 // - 1/10

20*x^2+2*x-(1/10) = 0

20*x^2+2*x-1/10 = 0

20*x^2+2*x-1/10 = 0

DELTA = 2^2-(-1/10*4*20)

DELTA = 12

DELTA > 0

x = (12^(1/2)-2)/(2*20) or x = (-12^(1/2)-2)/(2*20)

x = (2*3^(1/2)-2)/40 or x = (-2*3^(1/2)-2)/40

x in { (-2*3^(1/2)-2)/40, (2*3^(1/2)-2)/40 }

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